In the diagram above, QRS is a straight line, QP//RT, PRQ = ...
In the diagram above, QRS is a straight line, QP//RT, PRQ = 56°, ∠QPR =84° and ∠TRS = x°. Find x
A.
28°
B.
40°
C.
44°
D.
84°
E.
124°
Correct answer is B
< PQR = 180° - (84° + 56°)
= 40°
\(\therefore\) x = 40° (corresponding angles QP// RT)
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