[3(6x) - 5][2(6x)m + 1]
[3(6x) + 5][2(6x) - 1]
[(6x) - 5][3(6x) + 1]
[2(6x) + 5][3(6x) - 1]
Correct answer is B
62x + 1 + 7(6x) - 5
Let 6x = y....(i)
6yx + 7y - 5 = 0
(3y + 5)(2y - 1) = 0.....(i)
Subt. for y from eqn. (i) in eqn. (ii)
= [3(6x) + 5][2(6x) - 1]