The density of a certain oil on frying becomes 0.4 kgm\(^...
The density of a certain oil on frying becomes 0.4 kgm−3 with the volume of 20m3. what will be its initial volume when its initial density is 0.8 kgm−3 assuming no loss of oil due to spillage?
12m3
10m3
8m3
5m3
Correct answer is B
Density (D) = massvolume
∴
= 0.4 \times 20 = 8kg
The initial volume = \frac{Mass}{\text{Initial density}}
= \frac{8}{0.8} = 10m^{3}
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