Evaluate ∫21(6x2−2x)dx
...Evaluate ∫21(6x2−2x)dx
16
13
12
11
Correct answer is D
∫21(6x2−2x)dx=[6x33−2x22]21=[2x3−x2]21
= [2(2)3 - (2)2] – [2(1)3 - (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11
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