Find the value of \(\frac{tan 60^o - tan 30^o}{tan 60^o +...
Find the value of tan60o−tan30otan60o+tan30o
4√3
2√3
1
12
Correct answer is D
tan60o−tan30otan60o+tan30o=√3−1√3√3+1√3=(√3√3−1√3)÷(√3√3+1√3)=(3−1)(3+1)=24=12
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