In the diagram above, if the internal resistance of the cell...
In the diagram above, if the internal resistance of the cell is zero, the ration of the powers P1 and P2 dissipated by R1 and R2
A.
R2/R1
B.
R1/R2
C.
R1+R2/R1
D.
R1+R2/R2
Correct answer is A
Power = IV = I2R = V2/R
In terms of e.m.f E, of a cell we have
IE = I2R = E2/R
∴P1 = E2/R; P2 = E2/R2/E2/R2
= E2/R1 x R2/E2 = R2/R1
∴P1/P2 = R2/R1
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