50.0N
120.0N
200.0N
240N
Correct answer is B
V.R = \(\frac{1}{sin\theta} = \frac{1}{sin 30} = 2\)
M.A = \(\frac{E \times V.R}{100} = \frac{50 \times 2}{100} = 1\)
Effort = \(\frac{load}{M.A} = \frac{120}{1} = 120N\)
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