A gas with initial volume of 2 X 10-6m3 is allowed to exp...
A gas with initial volume of 2 X 10-6m3 is allowed to expand to six times its initial value at constant pressure of 2 x 105Nm-2. The work done is?
2.0 J
4.0 J
12.0 J
2.4 J
Correct answer is A
P = F/A => F = PA = PV/L
Volume V\(_2\) = 6 * 2 x 10\(^{-6}\)
W = PΔV = 2 x 10\(^5\) * (12 x 10\(^{-6}\) - 2 x 10\(^{-6}\))
= 2 x 10\(^5\) 10 x 10\(^{-6}\)
= 2.0J