A charge of 2.0 x 10\(^{-5}\) C experiences a force of 80N in a uniform electric field. Calculate the magnitude of the electric field intensity
8.0 x 106 NC-1
4.0 x 106 NC-1
4.0 x 104 NC-1
2.0 x 104 NC-1
Correct answer is B
E = \(\frac{F}{Q} = \frac{80}{2 \times 10^{-5}}\)
= 4 x 10\(^6\) NC\(^{-1}\)