If y = x sinx, find dy/dx when x = π/2.
-π/2
-1
1
π/2
Correct answer is C
y = x sin x dy/dx = 1 x sinx + x cosx = sinx + x cosx At x = π/2, = sin (π/2) + (π/2) cos (π/2) = 1 + (π/2) x (0) = 1
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