23.52°
24.50°
29.52°
29.82°
Correct answer is B
\(p . q = |p||q|\cos \theta\)
\(156 + 70 = (\sqrt{13^{2} + 14^{2}})(\sqrt{12^{2} + 5^{2}}) \cos \theta\)
\(226 = (\sqrt{365})(13) \cos \theta\)
\(\frac{226}{13\sqrt{365}} = \cos \theta\)
\(\cos \theta = 0.9099\)
\(\theta = 24.50°\)