If 20 cm\(^3\) of sodium hydroxide was neutralized by 20 cm\(^3\) of 0.01 mol dm3 tetraoxosulphate(VI) acid, what is the concentration of the solution?

A.

0.010

B.

0.020

C.

0.100

D.

0.150

View answer & explanation

Correct answer is B

\(frac{CaVa}{CbVb}\)  = \(frac{Na}{Nb}\)

( 0.01 X 20 ) / (Cb X 20) = 1 / 2

cross multiply → Cb = (0.01 X 20 X 2) / ( 20 X 1) 

Cb = 0.02 mol/dm\(^3\)

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