If 20 cm3 of distilled water is added to 80cm 3 of 0. 50 ...
If 20 cm3 of distilled water is added to 80cm 3 of 0. 50 mol dm-3 hydrochloric acid, the new concentration of the acid will be
0.10mol dm-3
0.20mol dm-3
0.40mol dm-3
2.00mol dm-3
Correct answer is C
\(V_1\) = 80cm3, \(C_1\) = 0.5mol/dm3
\(C_2\) = ? \(V_2) = 20cm3 + 80cm3 = 100cm3
using the dilution formula, \(C_1 V_1 = C_2 V_2\)
0.5 x 80 = \(C_2\) x 100
\(C_2 = \frac{ 40}{100}\) = 0.4mol\(dm^{-3}\)
What volume of 0.5M H2SO4 will exactly neutralize 20cm3 of 0.1M NaOH Solution? ...
How many carbon atoms are there in a benzene ring? ...
Diamond is a bad conductor of electricity because its bonding electrons are used in ...
Alkanoates are formed by the reaction of alkanoic acid with? ...
What is the chemical symbol for Bismuth? ...
Hydrogen is readily released when dilute hydrochloric acid reacts with ...
Which of the following types of bonding does not involve the formation of new substance? ...
Which of the following methods is suitable for preparing insoluble salts? ...