consider the reaction represented by the following equation: 2SO\(_2\) + O\(_2\) ⇌ 2SO\(_3\)
A decrease in the pressure of the reaction would
decrease in the concentration of SO\(_2\)
have no effect on the reaction
shift the equilibrium position to the left
shift the equilibrium position to the right
Correct answer is C
Decrease in pressure favors the side with higher volume thus the equilibrium position will shift to the left