The relative atomic mass of a naturally occurring lithium consisting of 90% \(^7 _3\)Li and \(^6 _3\)10% Li is

A.

6.9

B.

7.1

C.

6.2

D.

6.8

View answer & explanation

Correct answer is A

R.A.M = m\(_1 \alpha_1\) + m\(_2 \alpha_2\)

= 7(90/100) + 6(10/100)

= 6.3 + 0.6

= 6.9

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