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The number of molecules of Carbon(iv)Oxide produced when ...

The number of molecules of Carbon(iv)Oxide produced when 10.0g of CaCO3 is treated with 0.2dm3 of 1 Mole of HCL in the equation

CaCO3 + 2HCL ⇒  CaCl2  + H2 O + CO2  , is?

A.

1.00 X 1023

B.

6.02 X 1023

C.

6.02 X 1022

D.

6.02 X 1024

Correct answer is C

1 mole of CaCO3 = 100g or  6.02 X 1023

liberated 1 mole of CO2 or 44g or 6.02 X 1023

 

:100g =  6.02 X 1023

10g of CaCO3 = x

cross multiply

[10g X 6.02 X 1023] / 100g = x

⇒ x = 6.02 X 1022

 

Since 

 6.02 X 1023 of CaCO3 liberated 6.02 X 1023 of CO2

 

⇒ 6.02 X 1022 of CaCO3 will liberate 6.02 X 1022 of CO2