What mass of copper in gram would be deposited by a current of 1.00ampere passing for 965 seconds through copper(II) tertraoxosulphate (VI) solution? [Cu 63.5; If = 96500c]
0.32
0.64
3.18
6.35
9.65
Correct answer is A
Recall that two faradays ( 2 X 96500 ) will be required to discharge 1 mole of a divalent ion like Cu.
2 X 96500 will deposit 63.5g of Cu
And 965C wiil deposit x-grams
CROSS MULTIPLY
(965 X 63.5) ÷ ( 2 X 96500)
= 0.3175