A primary alkanol has a molecular mass of 60. What is the...
A primary alkanol has a molecular mass of 60. What is the structural formula of the compound? [C= 12.0, H= 1.0, O= 16.0)
A
B
C
D
Correct answer is B
Alkanols have the formula CnH2n+1OH.
⇒ 12n+(1×(2n+1))+16.0+1.0=60
= (14n +18 = 60\)
n=60−1814=4214=3
Hence, the alkanol is gotten by putting n=3,
=C3H7OH
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