How many grams of HBr would exactly be required to react with 2 g of propyne? (C =12, H=1, Br = 80)
4.1g
6.1g
8.1g
16.2g
Correct answer is C
2HBr + C3H4 \(\to\) C3H6 + 2Br
162gms of HBr reacts with 40gms of propyne 2gms of propyne will react with
\(\frac{162}{40} \times \frac{2}{1}\) = 8.1gms HBr