Al(s) + Cu2+(aq) → Al3+(aq) + Cu(s)
2Al(s) + Cu2+(aq) → 2Al(aq) + Cu(s)
2Al(s) + 3Cu2+(aq) → 3Cu(s) + 2Al3+(aq)
3Al(s) + 2Cu2+(aq) → Cu(s) + 3Al3+(aq)
Correct answer is C
Al(s) → Al3+(aq) + 3e- ______(i)
Cu2+(aq) + 2e- → Cu(s) ________(ii)
To balance the electrons, multiply equation (i) by 2 and equation (ii) by 3 and then add the resulting equations
2Al(s) →2Al3+(aq) + 3e-
3cu2+(aq) + 6e- →3Cu(s)
2Al(s) + 3Cu2+(aq) → 3Cu(s) + 2Al3+(aq)
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