Consider the following reaction equation: CaCO$_{3(s)}$ + 2HCI$_{(aq)}$ → CaCl$_{2(aq)}$ + H$_2$O$_{(l)}$ + CO$_{2(g)}$. What mass of CaCI$_2$ would be obtained when 25.0g of CaCO$_{3(s)}$ is reacted with excess HCI$_{(aq)}$? [CaCO$_3 = 100; CaCI\(_2$ = 111]

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