The oxidation number of iodine in the iodate ion (IO -3) is

A.

-5

B.

-1

C.

+1

D.

+5

View answer & explanation

Correct answer is D

1O3
[oxidation number of 1] + [oxidation number of 0] x 3 = -1
x + -2 x 3 = 1
x - 6 = - 1
x = - 1 + 6 = +5

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