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A given volume of methane diffuses in 20 seconds. How lon...

A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH4 = 16; SO2 = 64]

A.

5 seconds

B.

20 seconds

C.

40 seconds

D.

60 seconds

E.

80 seconds

Correct answer is C

Applying the Graham's law defination; i.e,

R(SO2)R(CH4)=M(CH4)M(SO2)=t(CH4)t(SO2)

Where t(SO2) = ?, M(SO2) = 64

t(Ch4) = 20 sec, M(Ch4) = 16

therefore, t(SO2)20 = 6416

t(SO2)20 = 84

t(SO2) = 8 x 204

= 40 sec.