A given volume of methane diffuses in 20 seconds. How lon...
A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH4 = 16; SO2 = 64]
5 seconds
20 seconds
40 seconds
60 seconds
80 seconds
Correct answer is C
Applying the Graham's law defination; i.e,
R(SO2)R(CH4)=√M(CH4)M(SO2)=t(CH4)t(SO2)
Where t(SO2) = ?, M(SO2) = 64
t(Ch4) = 20 sec, M(Ch4) = 16
therefore, t(SO2)20 = √6416
t(SO2)20 = 84
t(SO2) = 8 x 204
= 40 sec.
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