Given that 32.0g sulphur contains 6.02 x 10 23 sulphur atoms how many atoms are there in 2.70g of aluminium? {Al = 27, S =32}

A.

6.02 x 10 23

B.

3.01 x 1022

C.

6.02 x 1022

D.

5. 08 x 1022

E.

3.01 x 1022

Correct answer is C

27g Aluminium = \(6.02 \times 10^{23}\)

1g Al = \(\frac{6.02 \times 10^{23}}{27}\)

2.7g Al = \(\frac{6.02 \times 10^{23}}{27} \times 2.7\)

= \(6.02 \times 10^{22} Al \) atoms