Elements X and Y have electronic configurations 1s\(^2\)2s\(^2\)2p\(^4\) and 1s\(^2\)2s\(^2\)2p\(^2\)3s\(^6\)3p\(^1\) respectively. When they combine, the formula of the compound formed is?
XY
YX
X2Y3
Y2X3
Correct answer is D
\(\frac{\text{Element X}}{1s^22s^21p^4}\)
Valency of X is 2
\(\frac{\text{Element Y}}{1s^22s^22p^63s^23P^1}\)
valency of Y is 3
There is an exchange of valency when a compound is being formed. Hence, we have Y\(_2\)X\(_3\)