If a solution contains 4.9g of tetraoxosulphate (VI) acid, calculate the amount of copper (II) oxide that will react with it
[Cu = 64, O = 16, S = 32, H = 1]

0.8g

4.0g

40.0g

80.0g

Correct answer is B

Equation of the reaction
H₂SO_4(g) + CuO_(s) → Cu_{4(aq) + H₂O

Relative molecular mass of H₂SO₄ = 1 + 2 + 32 + 16 + 4 = 98

Relative molecular mass of CuO = 64 + 16 =80

From the above equation, 98_s of H₂SO₄ reacts with 80_s of CuO.

∴ 4.9g of H₂SO₄ will react with

= (4.9 * 80)/98 of CuO = 392/98 = 4.0g}

See all Chemistry questions & answers

See more JAMB questions & answers

If a solution contains 4.9g of tetraoxosulphate (VI) acid, calculate the amount of copper (II) oxide that will react with it
[Cu = 64, O = 16, S = 32, H = 1]

Similar Questions

Aptitude Tests

If a solution contains 4.9g of tetraoxosulphate (VI) acid, calculate the amount of copper (II) oxide that will react with it [Cu = 64, O = 16, S = 32, H = 1]

Similar Questions

Aptitude Tests

If a solution contains 4.9g of tetraoxosulphate (VI) acid, calculate the amount of copper (II) oxide that will react with it
[Cu = 64, O = 16, S = 32, H = 1]