HCOOH
C2H5COOH
CH3COOH
C3H7COOH
Correct answer is C
Conc. of KOH = 39 x 0.02 = 0.78 g/dm3
25cm3 require 0.03 g of CnH2n + 1 COOH 1000CM3 → x x = (1000) / (25) x 0.03 = 1.2g
CnH2n + 1COOH + KOH → CnH2n + 1 COOK + H2O
from (MAVA) / (MB x VB) = (1) / (1) (MA x 1.2) / (0.02 x 0.78) = (1) / (1)
MA = 0.013
Con. = Molarity x Molecular Mass
Molecular Mass = (0.78) / (0.013) x 60
CnH2n + 1 COOH = 60
12n + 1 (2n + 1) + 12 + 32 + 1 = 6
14n = 60 - 46; n = (14) / (14) = 1
∴ CH3COOH
The elements in the periodic table are listed in order of increasing ...
What volume of CO2 at s.t.p would be obtained by reacting trioxocarbonate (IV) with excess acid? ...
Which of the following represents the type of bonding present in ammonium chloride molecule? ...