Make x the subject of the formula:y = \(\frac {3x - 9c}{4x + 5d}\)

A.

x = \(\frac {(-9c - 5dy)}{4y - 3}\)

B.

x = \(\frac {-9c + 5dy}{4y - 3}\)

C.

x = \(\frac {(-9c + 5dy)}{4y - 3}\)

D.

x = \(\frac {-(9c + 5dy)}{4y - 3}\)

Correct answer is D

y = \(\frac {3x - 9c}{4x + 5d}\)

\(\frac {y}{1} = \frac {3x - 9c}{4x + 5d}\)

= y(4x + 5d) = 3x - 9c

= 4xy + 5dy = 3x - 9c

= 4xy - 3x = -9c - 5dy

= (4y - 3)x = -9c - 5dy

= x = \(\frac {-9c - 5dy}{4y - 3}\)

x = \(\frac {-(9c + 5dy)}{4y - 3}\)