x = \(\frac {(-9c - 5dy)}{4y - 3}\)
x = \(\frac {-9c + 5dy}{4y - 3}\)
x = \(\frac {(-9c + 5dy)}{4y - 3}\)
x = \(\frac {-(9c + 5dy)}{4y - 3}\)
Correct answer is D
y = \(\frac {3x - 9c}{4x + 5d}\)
\(\frac {y}{1} = \frac {3x - 9c}{4x + 5d}\)
= y(4x + 5d) = 3x - 9c
= 4xy + 5dy = 3x - 9c
= 4xy - 3x = -9c - 5dy
= (4y - 3)x = -9c - 5dy
= x = \(\frac {-9c - 5dy}{4y - 3}\)
x = \(\frac {-(9c + 5dy)}{4y - 3}\)