4
2
5
3
Correct answer is C
\(402_y = 102_ten\)
⇒ 4 x y\(^2\) + 0 x y\(^1\) + 2 x y\(^0\) = 102
⇒ 4y\(^2\) + 0 + 2 x 1 = 102
⇒ 4y\(^2\) + 2 = 102
⇒ 4y\(^2\) = 102 - 2
⇒ 4y\(^2\) = 100
⇒ y\(^2 = \frac {100}{4}\)
⇒ y\(^2\) = 25
∴ y = √25 = 5
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