If 4y is 9 greater than the sum of y and 3x, by how much is y greater than x?
3
6
9
12
Correct answer is A
4y - 9 > y + 3x; 4y - y > 3x + 9 3y > 3(x + 3); y = > \(\frac{3(x + 3)}{3}\) y > x + 3; y - 3 > x y is greater than x by 3
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