In XYZ, |YZ| = 32cm, < YXZ 53\(^o\) and XZY = 90\(^o\). Find, correct to the nearest centimetre, |XZ|
A.
31 cm
B.
25 cm
C.
20 cm
D.
13 cm
Correct answer is B
Tan 52\(^o\) = \(\frac{32}{\text{|XZ|}}\)
|XZ| = \(\frac{32}{Tan 52^o}\)
= 25cm