In the diagram, O is the centre of the circle. If SOQ is a diameter and < PRS is 38^o, what is the value of < PSQ

148^o

104^o

80^o

52^o

Correct answer is D

< SRP = < SQP = 38^o (angle in the same segment of a circle are equal)

But < SPQ = 90^o (angle in a semicircle)

also < PSQ + < SQP + < SPQ = 180^o (angles in a triangle = 180^o)

< PSQ + 38^o + 90^o = 190^o

< PSQ = 128^o = 180^o

PSQ = 180^o - 128^o

PSQ = 52^o

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In the diagram, O is the centre of the circle. If SOQ is a diameter and < PRS is 38o, what is the value of < PSQ

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In the diagram, O is the centre of the circle. If SOQ is a diameter and < PRS is 38^o, what is the value of < PSQ