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Marks 1 2 3 4 5
Frequency 2y - 2 y - 1 3y - 4 3 - y 6 - 2y

The table above is the distribution of data with mean equals to 3. Find the value of y.

A.

5

B.

2

C.

3

D.

6

View answer & explanation

Correct answer is B

Marks (x) 1 2 3 4 5  
Frequency (f) 2y - 2 y - 1 3y - 4 3 - y 6 - 2y 3y + 2
fx 2y - 2 2y - 2 9y - 12 12 - 4y 30 - 10y 26 - y

Mean = ∑fx∑f

3=26−y3y+2

3(3y+2)=26−y

9y+6=26−y

9y+y=26−6

10y=20⟹y=2

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