| Marks |
1 |
2 |
3 |
4 |
5 |
| Frequency |
2y - 2 |
y - 1 |
3y - 4 |
3 - y |
6 - 2y |
The table above is the distribution of data with mean equals to 3. Find the value of y.
| Marks (x) |
1 |
2 |
3 |
4 |
5 |
|
| Frequency (f) |
2y - 2 |
y - 1 |
3y - 4 |
3 - y |
6 - 2y |
3y + 2 |
| fx |
2y - 2 |
2y - 2 |
9y - 12 |
12 - 4y |
30 - 10y |
26 - y |
Mean = \(\frac{\sum fx}{\sum f}\)
\(3 = \frac{26 - y}{3y + 2}\)
\(3(3y + 2) = 26 - y\)
\(9y + 6 = 26 - y\)
\(9y + y = 26 - 6\)
\(10y = 20 \implies y = 2\)