\(\frac{1}{12}\)
\(\frac{1}{6}\)
\(\frac{2}{9}\)
\(\frac{3}{8}\)
Correct answer is C
Total = 8 + 12 + 4
= 24
\(\frac{8}{24} \times (\frac{12}{24} + \frac{4}{24}\))
= \(\frac{1}{3} \times (\frac{1}{2} + \frac{1}{6}\))
= \(\frac{1}{3} \times \frac{3 + 1}{6}\)
\(\frac{1}{3} \times \frac{4}{6} = \frac{2}{9}\)