A student measured the height of a pole as 5.98 m which i...
A student measured the height of a pole as 5.98 m which is less than the actual height. If the percentage error is 5%, find correct to two d.p the actual height of the pole.
6.29m
7.67m
7.18m
6.65m
Correct answer is A
%error=5%, measured height = 5.98m
let the actual height = y
error=x - 5.98 (since 'y' is more than 5.98)
%error = \(\frac{error}{actual height}\times 100%\)
5% = \(\frac{y - 5.98}{y}\times 100%\)
\(\frac{5}{100} = \frac{y - 5.98}{y}\)
5y = 100(y - 5.98)
5y = 100y - 598
5y - 100y = - 598
-95y = - 598
y = \(\frac{-598}{-95}\)
y = 6.29m( to 2 d.p).
If P = {1,2,3,4,5} and P \(\cup\) Q = {1,2,3,4,5,6,7}, list the elements in Q ...
Simplify; \(\frac{a}{b} - \frac{b}{a} - \frac{c}{b}\)...
If \(\frac{y-3}{2}<\frac{2y-1}{3}\), which of the following is true?...
If three unbiased coins are tossed, find the probability that they are all heads ...
Which of the following is true about parallelogram? ...
Find n if log\(_{2}\) 4 + log\(_{2}\) 7 - log\(_{2}\) n = 1...