A student measured the height of a pole as 5.98 m which i...
A student measured the height of a pole as 5.98 m which is less than the actual height. If the percentage error is 5%, find correct to two d.p the actual height of the pole.
6.29m
7.67m
7.18m
6.65m
Correct answer is A
%error=5%, measured height = 5.98m
let the actual height = y
error=x - 5.98 (since 'y' is more than 5.98)
%error = erroractualheight×100
5% = y−5.98y×100
5100=y−5.98y
5y = 100(y - 5.98)
5y = 100y - 598
5y - 100y = - 598
-95y = - 598
y = −598−95
y = 6.29m( to 2 d.p).
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