\(\frac{153}{250}\)
\(\frac{68}{111}\)
\(\frac{61}{100}\)
\(\frac{21}{33}\)
Correct answer is A
0.612 = \(\frac{0.612}{1}\) x \(\frac{1000}{1000}\)
= \(\frac{612}{1000}\)
= \(\frac{153}{250}\)
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