18cm
(18 + \(\frac{9\pi}{5}\))cm
(9 + \(\frac{9\pi}{5}\))cm
\(\frac{9\pi}{5}\)cm
Correct answer is B
Perimeter = 2r + \(\frac{\theta}{360}\) x 2\(\pi\)r 2(9) + \(\frac{36}{360}\) x 2 x \(\pi\) x 9 = 18 + \(\frac{9\pi}{5}\)
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