A bag Contains 2 red, 3 blue and 4 green identical balls. If two balls are picked at random one after the other without replacement, what is the probability that both are green?
\(\frac{1}{6}\)
\(\frac{1}{3}\)
\(\frac{16}{18}\)
\(\frac{3}{8}\)
\(\frac{4}{9}\)
Correct answer is A
No explanation has been provided for this answer.