A beam of light travelling in water is incident on a glass which is immersed in the water. The incident beam makes an angle of $40^o$ with the normal. Calculate the angle of refraction in the glass.

[Refractive index of water = 1.33, Refractive index of glass = 1.5]

$29.36^o$

$25.37^o$

$37.21^o$

$34.75^o$

Correct answer is D

$n_1$ =1.33; $n_2$ =1.5; i=40°; r= ?

from snell's law:

$n_1$ x sin i= $n_2$ x sin r

⇒1.33 x sin 40°=1.5 x sin r

⇒sin r = 0.5700

⇒r = $sin^{-1}$ (0.5700)

⇒ r = 34.75

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A beam of light travelling in water is incident on a glass which is immersed in the water. The incident beam makes an angle of $40^o$ with the normal. Calculate the angle of refraction in the glass.

[Refractive index of water = 1.33, Refractive index of glass = 1.5]

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A beam of light travelling in water is incident on a glass which is immersed in the water. The incident beam makes an angle of 40o40^o with the normal. Calculate the angle of refraction in the glass. [Refractive index of water = 1.33, Refractive index of glass = 1.5]

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A beam of light travelling in water is incident on a glass which is immersed in the water. The incident beam makes an angle of $40^o$ with the normal. Calculate the angle of refraction in the glass.

[Refractive index of water = 1.33, Refractive index of glass = 1.5]