A block of mass 0.5 kg is suspended at the 40 cm mark of ...
![A block of mass 0.5 kg is suspended at the 40 cm mark of a light metre rule AB that is pivoted at point E, the 90 cm mark, and is kept at equilibrium by a string attached at point D, the 60 cm mark, as shown in the figure above. Find the tension T in the string.
[Take g = \(10 ms-2\) ]](/img/aptitude-tests/questions/24541.png "A block of mass 0.5 kg is suspended at the 40 cm mark of a light metre rule AB that is pivoted at point E, the 90 cm mark, and is kept at equilibrium by a string attached at point D, the 60 cm mark, as shown in the figure above. Find the tension T in the string.
[Take g = \(10 ms-2\) ]")
A block of mass 0.5 kg is suspended at the 40 cm mark of a light metre rule AB that is pivoted at point E, the 90 cm mark, and is kept at equilibrium by a string attached at point D, the 60 cm mark, as shown in the figure above. Find the tension T in the string.
[Take g = \(10 ms-2\) ]
16.67N
15.67N
14.67N
18.67N
Correct answer is A
W = mg = 0.5 x 10 = 5 N
Since it's light, neglect the weight of the metre rule.
The effective tension T acting in the vertical direction = T sin 30°
From the second condition of equilibrium, sum of clockwise moments equal sum of anticlockwise moments
Taking moment at E
⇒ T sin 30° x 30 = 5 x 50
⇒ ∴T=250
T = \(\frac{250}{15}\) = 16.67N
Similar Questions
Which of the following i. \(\beta\)-particles ii. protons iii. neutrons iv. \(\alpha\)-particl...
Which of the following are true about the infra-red radiation? i. it is invisible ii. it is call...
Nuclear fission is preferred to nuclear fusion in the generation of energy because? ...
When two waves are superimposed on each other, the following occurrences are possible, except ...