3.3cm
6.5cm
7.5cm
10.8cm
15.0cm
Correct answer is C
F \(\alpha\) e and m \(\alpha\) F \(\frac{m_1}{e_1}\) = \(\frac{m_2}{e_2}\) \(\frac{10}{5}\) = \(\frac{15}{e_2}\) e2 = 7.5cm
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