A parallel plate capacitor separated by an air gap is made of $0.8m^2$ tin plates and 20 mm apart. It is connected to 120 V battery. What is the charge on each plate?
Take $ε_o$ = $8.85×10^-12 Fm^-1$

3.54nC

42.5nC

35.4nC

4.25nC

Correct answer is B

A= $0.8m^2$ d= 20mm = $\frac{20}{1000}$ = 0.02m

v =120v; $ε_oA$ = $8.85 × 10^-12 fm^-1$

C = $\frac{ε_oA}{d}$

C = $\frac{8.85 × 10^-12×0.8}{0.02}$

C= $3.54 × 10^-10 F$

Q= CV

⇒ $3.54 × 10^-10$ × 120 = $4.25×10^-8c$

Q= $42.5 × 10^-9c$ = 42.5nC

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A parallel plate capacitor separated by an air gap is made of $0.8m^2$ tin plates and 20 mm apart. It is connected to 120 V battery. What is the charge on each plate?
Take $ε_o$ = $8.85×10^-12 Fm^-1$

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A parallel plate capacitor separated by an air gap is made of $0.8m^2$ tin plates and 20 mm apart. It is connected to 120 V battery. What is the charge on each plate?
Take $ε_o$ = $8.85×10^-12 Fm^-1$