In a series R-L-C circuit, R = 10Ω, Xc= 4...
In a series R-L-C circuit, R = 10Ω, Xc= 4Ω and XL = 9Ω. The impedance of the circuit is
4.1Ω
5.0Ω
10.8Ω
11.2Ω
Correct answer is D
The impedance for a RLC circuit is
Z=√R2+(XL−XC)2
= √102+(9−4)2
= √125
= 11.18Ω ≊ 11.2\Omega