−3 < x < \(\leq\)3
−2< x < \(\leq\)5
2< x < \(\geq\) −5
−1< x \(\geq\) \(\leq\)2
Correct answer is B
S = {0, 1, 2, 3, 4, 5}
T = {− 1, 0, 1, 2}
S \(\cup\) T = {− 1, 0, 1, 2, 3, 4, 5 }
⇒ − 2 < x ≤ 5
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