If nP3−6(nC4)=0, find the value of n....
If nP3−6(nC4)=0, find the value of n.
5
6
7
8
Correct answer is C
nP3−6(nC4)=0n!(n−3)!−6(n!(n−4)!4!)=0n!(n−3)!=6(n!(n−4)!4!)n!((n−4)!4!)=6n!(n−3)!((n−4)!4!)=6(n−3)!(n−4)!(n−3)!=64!(n−4)!(n−3)(n−4)!=64×3×2×11(n−3)=]14n−3=4n=4+3n=7
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