\(\frac{{2x+1}^3}{8}\) + C
\(\frac{{2x+1}^4}{8}\) + C
\(\frac{{2x+1}^4}{4}\) + C
\(\frac{{2x+1}^2}{6}\) + C
Correct answer is B
Recall chain rule:
u = 2x +1; du = 2dx → dx = \(\frac{du}{2}\)
u\(^3\) = ∫ u\(^3\) \(\frac{du}{2}\) → \(\frac{1}{2}\) ∫ u\(^3\)
= \(\frac{1*u^4}{2*4}\)
= \(\frac{u^4}{8}\) → \(\frac{{2x+1}^4}{8}\) + C
Simplify 3\(\sqrt{27x^3y^9}\)...
find the mean deviation of 1, 2, 3 and 4 ...
The bearing of Y from X is 060o and the bearing of Z from Y = 060o. Find the bearing of X from Z...
The value of (0.03)3 - (0.02)3 is ...
Solve the equation 4/a + 1/5a = 3 ...
Evaluate \(\frac{12.02 \times 20.06}{26.04 \times 60.06}\), correct to three significant figures....
If X = {all the perfect squares less than 40} Y = {all the odd numbers fro, 1 to 15}. Find X ∩ ...
Find the range of values of m which satisfy (m - 3)(m - 4) < 0...