A Motor Tyre is inflated to pressure of 2.0 x 10⁵Nm^-2 when the temperature of air is 27^oC. What will be the pressure in it at 87^oC assuming that the volume of the Tyre does not change?

2.6 x 10⁵Nm^-2

2.4 x 10⁵Nm^-2

2.2 x 10⁵Nm^-2

1.3 x 10⁵Nm^-2

Correct answer is B

\(\frac{p_1}{T_1}\) = \(\frac{p_2}{T_2}\)

\(\frac{2 \times 10^5}{27 + 273}\) = \(\frac{p_2}{87 + 273}\)

P₂ = 2.4 x 10⁵Nm^-2

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