The graph of the relation y = x2 + 2x + k passes through the point (2, 0). Find the values of k
zero
-2
-4
-8
Correct answer is D
y = x2 + 2x + k at point(2,0) x = 2, y = 0 0 = (2)2 + 2(20 + k) 0 = 4 + 4 + k 0 = 8 + k k = -8
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