What is the place value of 9 in the number 3.0492?
\(\frac{9}{10000}\)
\(\frac{9}{1000}\)
\(\frac{9}{100}\)
\(\frac{9}{10}\)
Correct answer is B
Place value of 9 in 3.0492 = 0.009 = \(\frac{9}{1000}\)
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