n = 1
n = 2
n = 3
n = 5
Correct answer is C
\(\frac{5^{n +3}}{25^{2n -2}}\) = 5o \(\frac{5^{n + 3}}{5^{2(2n - 3)}}\) = 5o n + 3 - 4n + 6 = 0 -3n + 9 = 0 -3n = -9 n = \(\frac{-9}{-3}\) n = 3
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